Current Balance: The Magnetic Force
To explore how the magnetic field between two parallel current-carrying wires is affected by
different weights. To calculate and compare the value of 𝛍0 to the theoretical value of 𝛍0.
1. Turn on the lizer and Start putting the weight on the conductor than turn it on. Than
measure the distance between the conductor and the board we would call it L. masseur
the thickness of the wire.
2. Draw point exactly in front of the conductor and put line 3cm above it and another one
3cm under it.
3. By adjusting the lizard on the board to the point we drew earlier. We going to use the
conductor knobe if the lizard was higher we will lower the knobe to make it pointing to
the point on the board, if the lizard was under the point we will increase the knobe to
make it point the the point we drew earlier.
4. We did that experience with six different weight than we got the (I) from the condoctore
and we used the equation (( L wire* L wire FEQ)/( L))+ Thickness wire = to get the D .
F = (ℓ2 μ0 i1 i2 )/(2ℼr) N (Eq. 1)
mg = (ℓ2 μ0 i2 )/(2ℼr)
i2 = [(2ℼr)/(ℓ2 μ0 )]mg = K mg A2 (Eq. 2)
K = (2ℼr)/(ℓ2 μ0 ) J (Eq. 3)
μ0 = (2ℼr)/(ℓ2 K) N/A2 (Eq. 4)
Measured and Calculated Variables:
Lmirror, whiteboard = 4.56 m
ℓ1 = 0.215 m
ℓ2 = 0.265 m
h = 0.27 m
r1 = ℓ1 (h /L) + [diameter of wire] = 0.215(0.27/4.56) + 0.0037 = 0.0164 m
Table 1 (r1 = 0.0164 m):
K and µ0 Calculations:
K experimental = 164773 J
K theoretical = (2ℼr1 )/(ℓ2 μ0 ) = (2ℼ * 0.0164)/(0.265 * 1.26 * 106 ) (Eq. 3)
K theoretical = 308608 J
% error = 100|K theoretical K experimental |/K theoretical = 46.6 % error
μ0, accepted = 1.26 * 106 N/A2
μ0, experimental = (2ℼr1 )/(ℓ2 K experimental ) = (2ℼ * 0.0164)/(0.265 * 164773) (Eq. 4)
μ0, experimental = 2.36 * 106 N/A2
% error = 100|μ0, theoretical μ0, experimental |/μ0, theoretical = 87.3 % error
1. Refer to graph above
2. Our experimental value for K was 164,773 J, while our theoretical value was 308,608 J,
giving us about a 46.6% error.
3. From our slope, we calculated that µ0 was 2.36 * 10-6 N/A2 and, compared to the
accepted value of µ0, which is 4ℼ * 10-6 N/A2, it gave us a percent error of about 87.3%.
4. A major source of error would probably be consistency in performing the experiment.
Since there were many different groups that collected this data, there was no regulation in
the way we each conducted the experiment. It may also be that, since the data relied on
each of our groups’ judgement, it was just not accurate. In addition, the board could have
also possibly been moved, of which the data relied on this distance between the board and
Purchase answer to see full