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Please read the instructions on the question paper before chosing to do the homework. homework is from the test book Statistic informés Decision using date Michael Sullivan 4th Édition
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Summary
7.2
2
7.3
25
7.4
25
8.1
27
8.2
35
8.1 UPPER LEG LENGTH
38
8.2 SAMPLING DISTRIBUTION
39
7.2
1. standard normal distribution.
2. 𝛼
3. 0.3085 (By symmetry, 45 and 35 are at the same distance from the mean.)
4. 0.4207 (The area under a point is zero.)
5.
a) Use normalcdf(-1e99,-2.45,0,1): 0.0071428147
b) Use normalcdf(-1e99,-0.43,0,1): 0.3335978513
c) Use normalcdf(-1e99, 1.35,0,1): 0.9114919484
d) Use normalcdf(-1e99, 3.49,0,1): 0.9997584447
6.
a) Use normalcdf(-1e99, -3.49,0,1): 2.415552975e-4
b) Use normalcdf(-1e99, -1.99,0,1): 0.0232953977
c) Use normalcdf(-1e99, 0.92,0,1): 0.8212136466
d) Use normalcdf(-1e99, 2.90,0,1): 0.9981341199
7.
a) Use normalcdf(-3.01,1e99,0,1): 0.9986936923
b) Use normalcdf(-1.59,1e99,0,1): 0.9440825968
c) Use normalcdf(1.78,1e99,0,1): 0.0375379306
d) Use normalcdf(3.11,1e99,0,1): 9.355044612e-4
8.
a) Use normalcdf(-3.49,1e99,0,1): 0.9997584447
b) Use normalcdf(-0.55,1e99,0,1): 0.7084403454
c) Use normalcdf(2.23,1e99,0,1): 0.0128736783
d) Use normalcdf(3.45,1e99,0,1): 2.803412199e-4
9.
a) Use normalcdf(-2.04,2.04,0,1): 0.9586498109
b) Use normalcdf(-0.55,0,0,1): 0.2088403459
c) Use normalcdf(-1.04,2.76,0,1): 0.8479399044
10.
a) Use normalcdf(-2.55,2.55,0,1): 0.989227659
b) Use normalcdf(-1.67,0,0,1): 0.4525403416
c) Use normalcdf(-3.03,1.98,0,1): 0.974925468
11.
a) Use normalcdf(-1e99,-2,0,1)+normalcdf(2,1e99,0,1): 0.045500124
b) Use normalcdf(-1e99,-1.56,0,1)+normalcdf(2.56,1e99,0,1): 0.064613585
c) Use normalcdf(-1e99,-0.24,0,1)+normalcdf(1.20,1e99,0,1): 0.5202349066
12.
a) Use normalcdf(-1e99,-2.94,0,1)+normalcdf(2.94,1e99,0,1): 0.003282259
b) Use normalcdf(-1e99,-1.68,0,1)+normalcdf(3.05,1e99,0,1): 0.04476229081
c) Use normalcdf(-1e99,-0.88,0,1)+normalcdf(1.23,1e99,0,1): 0.2987782303
13. Use invNorm(0.1,0,1): -1.281551567
14. Use invNorm(0.2,0,1): -0.8416212335
*Point with x area to the right has 1-x are to the left:
15. Use invNorm(0.75,0,1): 0.6744897495
16. Use invNorm(0.65,0,1): 0.3853204726
*Points with x area in between, the lower bound has 1-x/2 are to the left, the upper bound is the
symmetrical value of the lower bound.
17. Use invNorm(0.005,0,1): -2.575829303 and +2.575829303.
18. Use invNorm(0.03,0,1): -1.88079361 and +1.88079361.
19. Use invNorm(0.99,0,1): 2.326347877
20. Use invNorm(0.98,0,1): 2.053748911
21. Use invNorm(0.975,0,1): 1.959963986
22. Use invNorm(0.85,0,1): 1.03643338
23. Use normalcdf(35,1e99,50,7): 0.9839377721
24. Use normalcdf(65,1e99,50,7): 0.0160622279
25. Use normalcdf(-1e99,45,50,7): 0.2375251875
26. Use normalcdf(-1e99,58,50,7): 0.8734509941
27. Use normalcdf(40,65,50,7): 0.9073740008
28. Use normalcdf(56,68,50,7): 0.1906188963
29. Use normalcdf(55,70,50,7): 0.235387756
30. Use normalcdf(40,49,50,7): 0.3666377058
31. Use normalcdf(38,55,50,7): 0.7192367145
32. Use normalcdf(56,66,50,7): 0.1845474626
*The n-th percentile is the X-value for which the area to the left of X is n/100.
33. Use invNorm(0.09,50,7): 40.614714476
34. Use invNorm(0.90,50,7): 58.97086097
35. Use invNorm(0.81,50,7): 56.14527403
36. Use invNorm(0.38,50,7): 47.86163446
37.
a) Use normalcdf(-1e99,20,21,1): 15.86552596%
b) Use normalcdf(-22,1e99,21,1): 15.86552596%
c) Use normalcdf(19,21,21,1): 47.7249...
