Mathematics
how do you solve x^2+8x - 48 = 0

Question Description

Can someone help me solve this function: x^2+8x - 48? I don't know how to deal with this type of questions. Thanks!

Final Answer

x^2 + 8x - 48 = 0; To solve this function, you want to factor -48 first. Notice that 48 = -4 * 12 and -4x + 12x = 8x. So the function can be written as (x-4)(x+12) = 0; Then x1 =4, x2 = -12

Charles I (105)
Purdue University

Anonymous
Top quality work from this tutor! I’ll be back!

Anonymous
It’s my second time using SP and the work has been great back to back :) The one and only resource on the Interwebs for the work that needs to be done!

Anonymous
Thanks, good work

Studypool
4.7
Trustpilot
4.5
Sitejabber
4.4

Brown University





1271 Tutors

California Institute of Technology




2131 Tutors

Carnegie Mellon University




982 Tutors

Columbia University





1256 Tutors

Dartmouth University





2113 Tutors

Emory University





2279 Tutors

Harvard University





599 Tutors

Massachusetts Institute of Technology



2319 Tutors

New York University





1645 Tutors

Notre Dam University





1911 Tutors

Oklahoma University





2122 Tutors

Pennsylvania State University





932 Tutors

Princeton University





1211 Tutors

Stanford University





983 Tutors

University of California





1282 Tutors

Oxford University





123 Tutors

Yale University





2325 Tutors