how do you solve x^2+8x - 48 = 0

User Generated

Gbfvan

Mathematics

Question Description

Can someone help me solve this function: x^2+8x - 48? I don't know how to deal with this type of questions. Thanks!

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Explanation & Answer

x^2 + 8x - 48 = 0; To solve this function, you want to factor -48 first. Notice that 48 = -4 * 12 and -4x + 12x = 8x. So the function can be written as (x-4)(x+12) = 0; Then x1 =4, x2 = -12

Puneyrf V (105)
Purdue University

Anonymous
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