North American University Acceleration Vector Physics Questions

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NaanYhfv

Science

North American University

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vx =

dx(t )
dy (t )
, vy =
dt
dt

vx =

d ( t )
=
dt

y (t ) = 3.0 −  t 2
d (3.0 −  t 2 )
= −2  t
dt
The velocity Vector= ( , −2  t )
vy =

v = (2.4m / s, (−2.4m / s 2 )t )
v = (2.4, −2.4t )
Acceleration as a function of time
dv( x)
dy
ax =
, ay =
dt
dt
d (2.4)
ax =
=0
dt
d (−2.4t )
ay =
= −2.4
dt
acceleration vector a = (0, −2.4)

c)

v = (2.4, −2.4t )
At t=2.0
v = (2.4, −2.4(2) = (2.4m / s, −4.8m / s)
Magnitude = vx 2 + vy 2
= 2.42 + (−4.8)2
= 5.4m / s
Direction of the velocity vector 
v
 = tan −1 ( y )
...

FxvyyrqGhgbeMvff (9067)
Cornell University

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