## Question Description

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## Explanation & Answer

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vx =

dx(t )

dy (t )

, vy =

dt

dt

vx =

d ( t )

=

dt

y (t ) = 3.0 − t 2

d (3.0 − t 2 )

= −2 t

dt

The velocity Vector= ( , −2 t )

vy =

v = (2.4m / s, (−2.4m / s 2 )t )

v = (2.4, −2.4t )

Acceleration as a function of time

dv( x)

dy

ax =

, ay =

dt

dt

d (2.4)

ax =

=0

dt

d (−2.4t )

ay =

= −2.4

dt

acceleration vector a = (0, −2.4)

c)

v = (2.4, −2.4t )

At t=2.0

v = (2.4, −2.4(2) = (2.4m / s, −4.8m / s)

Magnitude = vx 2 + vy 2

= 2.42 + (−4.8)2

= 5.4m / s

Direction of the velocity vector

v

= tan −1 ( y )

...