General Questions, Math Assignment Homework Help

timer Asked: May 15th, 2016
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Question Description

I need some help with some Questions about math

Tutor Answer

School: UT Austin

Attached is word file and pdf (same thing)Please let me know if you have any questions about anything provided.

Exponent rules
Questions 4, 6, 8, 10, 12 and 14
The first section deals with negative exponents and rewriting the expression to have only
positive exponents. To change a negative exponent into a positive exponent, you want
to move the both the base and the exponent to the other side of a fraction. If there is no
fraction to begin with then you put the base/exponent into the denominator and place a 1
in the numerator.
Attached below is a single picture with all 5 problems. I wrote out some basic rules on
the top of the page. Each final answer is boxed in red.
4. First start by getting rid of the negative exponent, by moving the -5 to the bottom of
the fraction. The only thing that changes by doing this is the sign on the exponent.
Now take (-5) squared. Remember that a negative number squared (or to any other even
power) is always positive. The final answer is shown
6. Follow the general steps outlined in problem 4: Get rid of the negative exponent
and simplify. The difference between this problem and the last is the location of the
negative sign. When written in front, that means -(7)2 or in words the negative of seven
squared. What we had in the last problem was negative 5 squared. There is an
important difference. In problem 4, we squared a negative number, that is -5*-5 = 25.
However, in this problem you are taking the negative of a number that has been squared,
or -(7*7) = - 49.
8. Start by moving the entire fraction to the denominator and raising it to the positive
power. Now you need to distribute the exponent into the parenthesis. What you need
to do next is remember that when you divide by a fraction it is the same thing as
multiplying by the reciprocal (fraction flipped so the top becomes the bottom and the
bottom becomes the top). Finally cube the numbers.
10. Get rid of the negative exponent by moving 5t to the denominator. Distribute the
exponent. Take the third power where you can.
12 So this problem is a little different than the others seen before. Here we have
something (the 5) that is not raised to a negative exponent. That means when we get rid
of the negative exponent by moving things into the denominator, you can only move
things already raised to t...

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awesome work thanks

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