If y varies jointly as x and z y = k*x*z ------ Solve for "k" using "y = 12 when x = 9 and z = 3" 12 = k*9*3 k = 12/27 = 4/9 ---- Equation: y = (4/9)*x*z ---------

Find z when y = 6 and x = 15. ----- 6 = (4/9)*15*z ---- 6 = (20/3)z Ans: z = 18/20 = 9/10

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if p=20 then g= 20*10/2 if p=1 then g= 1*10/2 if p=28 then g=28*10/2 if p=40 then g=40*10/2 if p=100 then g=100*10/2