If y varies jointly as x and z y = k*x*z ------ Solve for "k" using "y = 12 when x = 9 and z = 3" 12 = k*9*3 k = 12/27 = 4/9 ---- Equation: y = (4/9)*x*z ---------

Find z when y = 6 and x = 15. ----- 6 = (4/9)*15*z ---- 6 = (20/3)z Ans: z = 18/20 = 9/10

2

if p=20 then g= 20*10/2 if p=1 then g= 1*10/2 if p=28 then g=28*10/2 if p=40 then g=40*10/2 if p=100 then g=100*10/2

3

"P varies inversely as h" ----> P = k/h

P = k/h

7 = k/0.7

7*0.7 = k

4.9 = k

k = 4.9

-------------

P = k/h

P = 4.9/h

P = 4.9/12

P = 0.408333333

please choose my answer i am waiting

Jul 2nd, 2014

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