zaarsmakhanz@yahoo.com

label Physics
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A stone of mass 2kg is dropped from a height of 50m.its K.E after two seconds will be...?
a:9.8J
b:19.6J
c:39.6J
d: none

Jul 6th, 2014

Sure - Here we will use the Kinetic Energy formula: K = .5*(mass)*(velocity)

before we to that, however, we need to determine the velocity of the object...since it is free-falling, then it's velocity after 2 seconds will be: v=gt = (9.81)*(2) = 19.62 m/s

Back to out KE equation: K = .5*2*19.62 = 19.62 J

The answer is b.

I'm quite proficient in physics.  Please feel free to contact me directly for assistance in the future.  Thanks.

Jul 6th, 2014

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Jul 6th, 2014
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