The University of Tennessee Chattanooga Power Simulation Lab Report

User Generated

Zbunzzq3000

Engineering

The University of Tennessee Chattanooga

Description

Unformatted Attachment Preview

Power Correction Using Capacitors Lab 3 (ETAP) Pre Experiment Question: 1. An 8 MW, 4 MVAR load is supplied at 13.8kV through a feeder with an impedance of 1 + j2 Ω. What is the input power to the feeder? (MW and MVAR) Start with calculating the current, and then figure out the line losses. 1|Page Power Correction Using Capacitors Lab 3 (ETAP) Experiment (This week we will be working in ETAP.) 1. Simulate the pre-lab problem in ETAP. 2. Does your simulation validate your hand calculation? (What mode should you be running in to show all three phases?) 3. Add to the simulation a compensating capacitor at the load. This capacitor can be varied from 0.5 – 10 MVAR in 0.5 MVAR steps. 4. What capacitor MVAR value minimizes the real power line losses? 5. What capacitor MVAR value minimizes the MVA flow into the feeder? 6. For the system, plot the real and reactive line losses as the capacitor value is varied from 0.5 – 10 MVAR. 2|Page Power Correction Using Capacitors Lab 3 (ETAP) Instructions for problem 2.32 in ETAP (page 84) First create a new project by clicking on the blank page icon. In the dialog box, only worry with the name. All of the other defaults are fine. Once you have a blank canvas, use the icons on the right side of the page to create the single line. You will need to use the grid, bus, impedance, capacitor, and the lumped load. When you are through, the single line should look something like this but without all the numbers. Next is to enter data into each of the elements. You will only need to enter data in one tab on each of the items. 3|Page Power Correction Using Capacitors Lab 3 (ETAP) On the grid editor, go to the ratings tab and enter 14.98 in the rated kV spot. Yes, this is not 13.8, but with the voltage drop through the line, the load should be at 13.8kV. 4|Page Power Correction Using Capacitors Lab 3 (ETAP) On the impedance editor, go to the rating tab and click the “Ohms” button at the bottom, and then enter 1 in the R and 2 in the X boxes. 5|Page Power Correction Using Capacitors Lab 3 (ETAP) Next is the lumped load editor. On the nameplate tab, enter 8 in the MW, 4 in the Mvar boxes. The rest of the boxes will be calculated. Also, move the slider all the way to the right where it shows 100% constant kVA. 6|Page Power Correction Using Capacitors Lab 3 (ETAP) The hardest element to set up will be the capacitor. On the rating tab, first click the kvar button at the top of the window to change it to the Mvar button as shown below. Next you will enter .5 in the Mvar / bank and 1 in the # of Banks box. As you do multiple simulations, you may just change the number in the banks box by using the arrows. You will need to perform calculations for 1-20 banks. 7|Page Power Correction Using Capacitors Lab 3 (ETAP) We are now ready to run the simulation. Start by clicking the balanced teeter-totter icon in the upper left to select balanced load flow mode. You can then run the simulation once by clicking the top button on the right hand side tool bar. (p arrow, V, arrow q on the button) Or, you can make the simulation automatically run every time you change something by clicking on the red and blue circular arrows just below the first button. 8|Page Power Correction Using Capacitors Lab 3 (ETAP) In order to get usable results, you will need to select the unit button, click the MVA button, and then select mva from the fly-out, and if it is in kva, click the M with the recycle arrow around it. The picture below shows a k with a recycle arrow because MVA is already selected. 9|Page Power Correction Using Capacitors Lab 3 (ETAP) There is still one piece of information missing. Click the little blue tv screen on the right hand side of the page. (Display options). The following dialog box will show up. Unfortunately, I made the screen shot of the wrong tab… On the results tab, put a check box by the “Branch losses” It is 2/3 of the way down the right hand side of the dialog box. 10 | P a g e Power Correction Using Capacitors Lab 3 (ETAP) Your results will look something similar to this below. Notice I have the automatic calculation selected, and it shows up as green. 11 | P a g e
Purchase answer to see full attachment
Explanation & Answer:
2 pages
User generated content is uploaded by users for the purposes of learning and should be used following Studypool's honor code & terms of service.

Explanation & Answer

Hi :). I am back, here is your lab 3 :). Hopefully we could work again in future.

Power Correction Using Capacitors
Lab 3 (ETAP)
Pre Experiment Question:
1. An 8 MW, 4 MVAR load is supplied at 13.8kV through a feeder with an impedance of 1 + j2 Ω.
What is the input power to the feeder? (MW and MVAR) Start with calculating the current, and
then figure out the line losses.
𝐹𝑖𝑟𝑡𝑠, 𝑐𝑎𝑙𝑐𝑢𝑙𝑎𝑡𝑒 𝐼:
𝐼=[

𝑆𝑙𝑜𝑎𝑑
]
𝑉

8 + 𝑗(4 − 𝑄𝑐𝑎𝑝 )
=[
]
13.80
=

8 − 𝑗(4 − 𝑄𝑐𝑎𝑝 )
13.80

�...


Anonymous
Goes above and beyond expectations!

Studypool
4.7
Trustpilot
4.5
Sitejabber
4.4

Related Tags