preparation of a complex iron salt

Anonymous
timer Asked: Jul 7th, 2014
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Question Description

calculate the number of grams (theoretical yield)of the final iron complex that can be produced from 10.00 g of ferrous ammonium sulfate hexahydrate

Tutor Answer

sobia
School: University of Maryland

the stoic ratio in rxn 2 is 6:2 So first you multiply 0.01202 by 6. Then divide that by 3 to give you the number of moles for Fe(OH)3 + 6H2O which gives you 0.0204 mol. then you use that to find the grams which you dont really need, i think. For the third rxn the ration is now 2;2 or 1:1. So what I did is divide 0.0204 mol by 2 and that gives u the number of moles for the iron complex = 0.0102 mol * 491.1 g/mol which gives a mass of 5.009 g. 

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Anonymous
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