the mean is 103 and the standard deviation of 15. find the third quartile which is the IQ score separating the top 25 percent from the others
75th percentile corresponds to a z-score of 0.6745. Thus, we need to be .6745 standard deviations to the right of the mean....in this case, that means you will need to be at 103+15*.6745 = 113.1175
Thus 75% of the population has an IQ score below 113.1175.
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