# In Game A, you simply lose \$1 every time you play.ii.In Game B, you count how much money you have left, Statistics Assignment Homework Help

Anonymous
account_balance_wallet \$5

### Question Description

Consider two games, Game A and Game B, with the following rules:

In Game A, you simply lose \$1 every time you play.ii.In Game B, you count how much money you have left.If it is an even number, you win \$3.Otherwise,

you lose \$5.
Say you begin with \$100 in your pocket.Clearly playing only one of these games exclusively is a losing strategy. Is there some combination of these two games that will yield a winning strategy?If so, what is it and why?

angel_cj
School: UT Austin

A winning strategy would be to alternate between games
starting with Game B.

If we start playing
Game B with \$100, since \$100 is an even number, we will win \$3. That will give
us \$103. Then we will play Game A, losing \$1 resulting in a balance of \$102.
Playing again Game B, having \$102 in the pocket (an even number) we will win
another \$3, resulting in a balance of \$105. Keeping playing using this strategy
will yield to a wining strategy. Below is a table showing the trend for the
first 11 plays with alternating between games.

Consider ...

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Anonymous
Top quality work from this guy! I'll be back!

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