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Algebra find solutions for f(x)

label Algebra
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select the approximate values of x that are solutions to f(x)=0, where f(x)=-4x^2+6x+9

Jul 19th, 2014

f(x)=-4x^2+6x+9

0 = -4x^2+6x+9

multiplying by -1 on both sides, we get

0 = 4x^2 - 6x -9

now the solution of this above quadratic equation is 

0 = (2x-3)(2x-3)

0 = (2x-3)^2

taking square root on both sides, we get

x = 3/2

Jul 19th, 2014

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Jul 19th, 2014
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Jul 19th, 2014
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