Write one equation of the line through the given points in slope-intercept form.

Algebra
Tutor: None Selected Time limit: 1 Day

the points are (2,1)&(-2,-1)

                       (3,7)&(-2,5)

        (5,6)&(3,10)

         Separate answers preferred(because i get confused a lot) Thanks in Advance

Jul 22nd, 2014

1)_ (2,1)&(-2,-1)

As m = Y2-Y1 / X2-X1, then

m = -1-1 / -2-2

m = -2 / -4

m = 1/2

Now we we either one points to find c from

Y = mX + c

putting the values of any points, we get

1 = (1/2)2 + c

1 = 1 + c

now we get        c = 0

So now we put the values of c and m in the equation Y = mX + c to get equation in slope intercept form, then

Y = 1/2X + 0

Hence         Y = 1/2X         Or

                   2Y = X

2)_ (3,7)&(-2,5)

As m = Y2-Y1 / X2-X1, then

m = 5-7 / -2-3

m = -2/-5

m = 2/5

Now we we either one points to find c from

Y = mX + c

putting the values of any points, we get

7 = (2/5)3 + c

29/5 = c

now we get        c = 29/5

So now we put the values of c and m in the equation Y = mX + c to get equation in slope intercept form, then

Hence    Y = 2/5X + 29/5               Or

              5Y = 2x =29

3)_ (5,6)&(3,10)

As m = Y2-Y1 / X2-X1, then

m = 10-6 / 3-5

m = 4 / -2

m = -2

Now we we either one points to find c from

Y = mX + c

putting the values of any points, we get

6 = (-2)5 + c

6 = -10 + c

6 + 10 = c

c = 16

now we get        c = 16

So now we put the values of c and m in the equation Y = mX + c to get equation in slope intercept form, then

Hence            Y = -2X + 16                 Or

                      Y = 16 - 2x

Jul 22nd, 2014

Studypool's Notebank makes it easy to buy and sell old notes, study guides, reviews, etc.
Click to visit
The Notebank
...
Jul 22nd, 2014
...
Jul 22nd, 2014
Dec 9th, 2016
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer