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Question Description
the points are (2,1)&(-2,-1)
(3,7)&(-2,5)
(5,6)&(3,10)
Separate answers preferred(because i get confused a lot) Thanks in Advance
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Explanation & Answer
1)_ (2,1)&(-2,-1)
As m = Y2-Y1 / X2-X1, then
m = -1-1 / -2-2
m = -2 / -4
m = 1/2
Now we we either one points to find c from
Y = mX + c
putting the values of any points, we get
1 = (1/2)2 + c
1 = 1 + c
now we get c = 0
So now we put the values of c and m in the equation Y = mX + c to get equation in slope intercept form, then
Y = 1/2X + 0
Hence Y = 1/2X Or
2Y = X
2)_ (3,7)&(-2,5)
As m = Y2-Y1 / X2-X1, then
m = 5-7 / -2-3
m = -2/-5
m = 2/5
Now we we either one points to find c from
Y = mX + c
putting the values of any points, we get
7 = (2/5)3 + c29/5 = c
now we get c = 29/5
So now we put the values of c and m in the equation Y = mX + c to get equation in slope intercept form, then
Hence Y = 2/5X + 29/5 Or5Y = 2x =29
3)_ (5,6)&(3,10)As m = Y2-Y1 / X2-X1, then
m = 10-6 / 3-5
m = 4 / -2
m = -2
Now we we either one points to find c from
Y = mX + c
putting the values of any points, we get
6 = (-2)5 + c6 = -10 + c
6 + 10 = c
c = 16
now we get c = 16
So now we put the values of c and m in the equation Y = mX + c to get equation in slope intercept form, then
Hence Y = -2X + 16 OrY = 16 - 2x
Ovyny_Zhefnyrra
(8863)
Cornell University
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