Write one equation of the line through the given points in slope-intercept form.

Algebra
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the points are (2,1)&(-2,-1)

                       (3,7)&(-2,5)

        (5,6)&(3,10)

         Separate answers preferred(because i get confused a lot) Thanks in Advance

Jul 22nd, 2014

1)_ (2,1)&(-2,-1)

As m = Y2-Y1 / X2-X1, then

m = -1-1 / -2-2

m = -2 / -4

m = 1/2

Now we we either one points to find c from

Y = mX + c

putting the values of any points, we get

1 = (1/2)2 + c

1 = 1 + c

now we get        c = 0

So now we put the values of c and m in the equation Y = mX + c to get equation in slope intercept form, then

Y = 1/2X + 0

Hence       Y = 1/2X         Or

                   2Y = X

2)_ (3,7)&(-2,5)

As m = Y2-Y1 / X2-X1, then

m = 5-7 / -2-3

m = -2/-5

m = 2/5

Now we we either one points to find c from

Y = mX + c

putting the values of any points, we get

7 = (2/5)3 + c

29/5 = c

now we get        c = 29/5

So now we put the values of c and m in the equation Y = mX + c to get equation in slope intercept form, then

Hence    Y = 2/5X + 29/5               Or

              5Y = 2x =29

3)_ (5,6)&(3,10)As m = Y2-Y1 / X2-X1, then

m = 10-6 / 3-5

m = 4 / -2

m = -2

Now we we either one points to find c from

Y = mX + c

putting the values of any points, we get

6 = (-2)5 + c

6 = -10 + c

6 + 10 = c

c = 16

now we get        c = 16

So now we put the values of c and m in the equation Y = mX + c to get equation in slope intercept form, then

Hence           Y = -2X + 16                 Or

                      Y = 16 - 2x

Jul 22nd, 2014

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