A solution that contains 9.30g organic compound per 200.0 ml of solution has an osmotic pressure of 0,171 atm at 27 degrees C. what is the molar mass of that organic compound?
Pressure = MRT 0.17 atm = M(0.0821 Latm/molK)(300K) M = 0.0581 mol/L Since the solution contained 7.480 g/300 mL solution, this would be equivalent to 7.480 g/300 mL X 1000 mL/L = 24.9 g/L Now, if you just take the ratio of those two calculations, you have: 24.9 g/L / 0.0581 mol/L = 429 g/mol
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