Engineering
Empire Beauty School Pittsburgh CH10 P Chart Fraction Defective Chart Worksheet

Empire Beauty School - Pittsburgh

### Question Description

Iβm studying and need help with a Engineering question to help me learn.

Chapter 6

Problems 5, 6, 12 & 13.

Chapter 10

Problems 4, 7 & 13.

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These are the solutions of chapter 6. Have a look and contact me if you have any doubts.will send the solution of chapter 10 within next 12 hours.

Step 1 β Tabulate the data for a center line for X-bar chart and R Chart
Subgroup
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25

Average (X-bar)
50.3
49.6
50.8
50.9
49.8
50.5
50.2
49.9
50.0
50.1
50.2
50.5
50.4
50.8
50.0
49.9
50.4
50.5
50.7
50.2
49.9
50.1
49.5
50.0
50.3

Range
0.73
0.75
0.79
0.74
0.72
0.73
0.71
0.70
0.65
0.67
0.65
0.67
0.68
0.70
0.65
0.66
0.67
0.68
0.70
0.65
0.60
0.64
0.60
0.62
0.60

Step 2 β Compute the UCL and LCL for X-bar and R charts

πΜΏ =

Μ
β25
π=1 π
25

πΜΏ = 50.22
πΜ =

β25
π=1 π
25

πΜ = 0.6784
Now, for sample size 4, A2 = 0.729, D3 = 0, D4 = 2.282
UCLX = πΜΏ + A2 πΜ
= 50.22 + (0.729*0.6784)
= 50.71

LCLX = πΜΏ - A2 πΜ
= 50.22 - (0.729*0.6784)
= 49.72
UCLR = D4 πΜ
= 2.228*0.6784
= 1.55
LCLR = D3 πΜ
= 0*0.6784
=0
Step 4 β Draw the control chart and plot the points

X-bar Chart
51.5
51
50.5
50
49.5
49
48.5
1

2

3

4

5

6

7

8

9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25

Average (X-bar)

Mean

UCL

LCL

R Chart
1.8
1.6
1.4
1.2
1
0.8
0.6
0.4
0.2

0
1

2

3

4

5

6

7

8

9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
Range

R bar

UCL

LCL

The process is out of control as the value of X-bar does not satisfy subgroup 3, 4, 14 and 23. So, eliminating
these four subgroups, revised control limits will be-

πΜΏ =

Μ
β21
π=1 π
21

πΜΏ = 50.17
πΜ =

β21
π=1 π
21

πΜ ...

Vishalc0 (142)
Purdue University
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