the average kinetic energy of 1 mole of gas at 102 degrees Celsius is:
the average kinetic energy of 1 mole of gas at 273 degrees Celsius is:
what pressure,in millimeters of mercury is equivalent to 2.13 atmospheres?
We need to know how many atoms in a gas molecule. Let us assume that a monatomic gas is then:
k - Boltsman konstant (k=1.38∙10^(-23))
T - absolute temperature (K), then:
E1 = 3/2 * 1.38∙10^(-23) * (102+273) =
E2 = 3/2 * 1.38∙10^(-23) * (273 + 273) =
Your next question:
1 atm = 760 millimeters of mercury, so 2.13 atm:
P = 2.13 * 760 = 1618.8 millimeters of mercury
Please choose my answer best. Thank you!
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