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chemistry questions concerning kinetic energy and moles of gas

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the average kinetic energy of 1 mole of gas at 102 degrees Celsius is:

the average kinetic energy of 1 mole of gas at 273 degrees Celsius is:

what pressure,in millimeters of mercury is equivalent to 2.13 atmospheres?

Jul 24th, 2014

We need to know how many atoms in a gas molecule. Let us assume that a monatomic gas is then:

E (kinetic) = 3/2 kT, where:

k - Boltsman konstant (k=1.38∙10^(-23))

T - absolute temperature (K), then:

E1 = 3/2 * 1.38∙10^(-23) * (102+273) = 

E2 = 3/2 * 1.38∙10^(-23) * (273 + 273) = 


Your next question:

1 atm = 760 millimeters of mercury, so 2.13 atm:

P = 2.13 * 760 = 1618.8 millimeters of mercury


Please choose my answer best. Thank you!


Jul 24th, 2014

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Jul 24th, 2014
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