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algebra math problem help

Algebra
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2 and y/3 x 7= 16 and 1/3

Jul 22nd, 2014

and means +

2 +7y/3= 16 + 1/3

Divide both sides by the LCD which is 3

(6 + 7y)/ 3= (48 + 1)/3 ; ( 6 + 7y)/3= (49)/ 3

Then you cross multiply

3(49)= 3( 6+7y) ; the 3 on both sides cancel out

49= 6 +7y

43=7y

y= 43/7


Jul 25th, 2014

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