A satellite is located 305 km above Earth. d = 305 km
What fraction of the acceleration at Earth’s surface is the acceleration due to gravity at the position of a satellite located 305 km above Earth?
Seeing as you state due to gravity, I will not include centripetal acceleration.
Force due to gravity is F=Gm1m2/r^2....since Fnet=ma...we simplify eqn to get:
a= F/m(sattelite) =(G*m(earth))/(r^2)
a= (G* Mearth)/(r^2)
a= (6.67*10^-11)(5.98 * 10^24)/ (305000)^2
a= 4.288 * 10^3 m/s^2
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