given a(2,0) b(8,4) show that P(3,5) is on the perpendicular bisector of AB by these two methods


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Method 2. Show PA=PB

I know the first methos so.

Nov 19th, 2017

PA^2= (3-2)^2+(5-0)^2=1+25=26

PB^2 =(3-8)^2+(5-4)^2=(-5)^2+1^2=25+1=26

PA^2=PB^2

PA =PB

Aug 6th, 2014

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Nov 19th, 2017
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