y=1/4x+1

Complete the ordered pairs

(4,__),(0,__)

Since, Equation is Y=(1/4)x+1

=>m=1/4 & x1=4 =>y1=mx1+b=>1/4(x1)+1=>1/4*4+1=>y1=2

so, (4,_)=(4,2)

Now, again , Y=(1/4)x+1

=>m=1/4 & x1=0 =>y1=mx1+b=>1/4(x1)+1=>1/4*0+1=>y1=1

so,(0,_)=(0,1)

Therefore,answer is : (4,__),(0,__)=(4,2),(0,1)

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