Microwave Energy and Radiation Analytical Chemistry Questions

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Science

Description

I have a homework that has 15 questions total, and the homework is in analytical chemistry. I need solution with steps. Thanks for the help.

Just check the pdf file.

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Explanation & Answer

Here it is. The attached word document has solutions to the problems. I've highlighted in yellow the answers that go into each cell on the that form. Just match the problem numbers (form and word doc) and look for the yellow highlights.Please ask if you have any questions.

For the first few problems you need to know
E = h*c/L = h*f
L*f = c
Wavenumber = 1 / wavelength
A = log(1/T) = -log(T) where A = absorbance and T = transmittance
A = ε*b*C
where A = absorbance, ε is a constant, C is concentration (Beer’s law)
And you need this EM spectrum

Question #1
E per photon =

(6.626x10−34 J ∙ s) ∗ (2.998x108 m ∙ s −1 )
h∗c
=
= 1.64x10−24 J
L
0.121 m

Question #2
E per photon =

(6.626x10−34 J ∙ s) ∗ (2.998x108 m ∙ s −1 )
h∗c
=
= 3.965x10−19 J
L
501x10−9 m

0.519 J
1 photon
x
= 1.31x1018 photons
1
3.965x10−19 J

Question #3
PART 1
c = L*f

(speed of light = wavelength * frequency)

frequency (v) =

c
2.998x108 m ∙ s −1
=
= 4.200x1014 s −1
L
713.8x10−9 m

E per photon = hf = (6.626x10−34 J ∙ s) ∗ (4.200x1014 s−1 ) = 2.783x10−19 J

2.783x10−19 J
1kJ 6.022x1023 photons
kJ
x
x
= 167.6
1 photon
1000J
mole of photons
mol

Light with this energy (L = 714nm) is RED. See the image below

PART 2
wavelength =

c
2.998x108 m ∙ s −1 109 nm
=
x
= 517.6 nm
frequency
5.792x1014 s −1
1m

E per photon = ℎ𝑓 = (6.626x10−34 J ∙ s) ∗ (5.792x1014 s−1 ) = 3.838x10−19 J

3.838x10−19 J
1kJ 6.022x1023 photons
kJ
x
x
= 231.1
1 photon
1000J
mole of photons
mol

Light with this energy is GREEN. See the image above

PART 3
frequency (v) =

c
2.998x108 m ∙ s −1
=
= 5.147x1014 s −1
L
582.5x10−9 m

E per photon = hf = (6.626x10−34 J ∙ s) ∗ (5.147x1014 s−1 ) = 3.410x10−19 J

3.410x10−19 J
1kJ 6.022x1023 photons
kJ
x
x
= 205.4
1 photon
1000J
mole of photons
mol

PART 4

251.6 kJ 1...


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