money problem explain with algebra

User Generated

fghqrag1621

Mathematics

Description

A collection of nickels, dimes, and quarters is worth $5.30. There are two more dimes than nickels and four more quarters than dimes. How many quarters are in this collection of coins?

User generated content is uploaded by users for the purposes of learning and should be used following Studypool's honor code & terms of service.

Explanation & Answer

Nickel = 5 cent

Dime =10 cent

Quarter =25 cent

no of nickels =x

no of dimes =x+2

no of quarters =x+2+4=x+6

Total value = 5x+10(x+2)+25(x+6)= 5x+10x+20+25x+150 = 40x+170 =530

40x =530-170=360

x=9

No of nickels =9

No of dimes =11

No of quarters= 15

Verification 9+0.05+11*0.1+15*0.25 dollars = 0.45+1.1+3.75=5.30



Anonymous
Just the thing I needed, saved me a lot of time.

Studypool
4.7
Trustpilot
4.5
Sitejabber
4.4