Mathematics
money problem explain with algebra

Question Description

A collection of nickels, dimes, and quarters is worth $5.30. There are two more dimes than nickels and four more quarters than dimes. How many quarters are in this collection of coins?

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Final Answer

Nickel = 5 cent

Dime =10 cent

Quarter =25 cent

no of nickels =x

no of dimes =x+2

no of quarters =x+2+4=x+6

Total value = 5x+10(x+2)+25(x+6)= 5x+10x+20+25x+150 = 40x+170 =530

40x =530-170=360

x=9

No of nickels =9

No of dimes =11

No of quarters= 15

Verification 9+0.05+11*0.1+15*0.25 dollars = 0.45+1.1+3.75=5.30


madhavant (2757)
New York University

Anonymous
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