 Mathematics
applications of single variable equations

### Question Description

The length of a rectangle is 8cm more than its width. The perimeter is 76 cm. find the dimensions of the rectangle ** Step by step process Since , perimeter of rectangle is P=2(l+w)

Let, the width is x cm then length must be x+8

Now, put these values in P=2(l+w)

or,76=2((x+8)+x)

or,76=2(2x+8)

or,76=4x+16

or,76-16=4x

or,60=4x

or,x=15 means width =15cm & length=15+8=23cm

Therefore, dimension, length=23cm & width=15cm Furious (72)
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