Applications of single variable equations

Question Description

I’m trying to learn for my Algebra class and I’m stuck. Can you help?

solve 2c = e ( j + m ) for m

Step by step instructions please!

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Final Answer

y = mx + b Always move the constant over first:

y - b = mx Then divide by the coefficient:

(y - b) / x = m

2c = e(j+m) Divide by e:

2c / e = j + m Subtract j:

2c / e - j = m

duingpung (540)
New York University

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