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I'm not sure how to work problem numbers 1 and 2.

label Algebra
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schedule 1 Day
account_balance_wallet $5

Oct 22nd, 2017

1.6(n+2)-4<-10   to solve this you can mostly think of it like an equal sign while getting n on one side and the numbers on the other. So to start +4 on both sides=

6(n+2)<-6 now divide by 6 on both sides(it is very important that whatever you do from one side of the equation you do to the other to keep your equation balanced)

n+2<-1  now -2 from both sides

n<-3 this means that n can be any number less than -3 but not -3

2. -5(2n-3)-6=-3(5n+1)-8 ok so your goal is to isolate n on one side of the equation with numbers on the other.

you can loosely follow order of operations backwards to achieve this so +6 to both sides =

-5(2n-3)=-3(5n+1)-2 now we are going to move the n to one side so +3(5n+1) to both sides =

3(5n+1)-5(2n-3)=-2 from here you have a couple of choices I will show you the one I like to use which is foil the 3 =

15n+3-5(2n-3)=-2 now foil the -5 =

15n+3-10n+15=-2 now combine like terms

5n+18=-2 next -18 from both sides

5n=-20 and finally divide the 5


Aug 15th, 2014

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