Time remaining:
I'm not sure how to work problem numbers 1 and 2.

Algebra
Tutor: None Selected Time limit: 1 Day

Aug 15th, 2014

1.6(n+2)-4<-10   to solve this you can mostly think of it like an equal sign while getting n on one side and the numbers on the other. So to start +4 on both sides=

6(n+2)<-6 now divide by 6 on both sides(it is very important that whatever you do from one side of the equation you do to the other to keep your equation balanced)

n+2<-1  now -2 from both sides

n<-3 this means that n can be any number less than -3 but not -3

2. -5(2n-3)-6=-3(5n+1)-8 ok so your goal is to isolate n on one side of the equation with numbers on the other.

you can loosely follow order of operations backwards to achieve this so +6 to both sides =

-5(2n-3)=-3(5n+1)-2 now we are going to move the n to one side so +3(5n+1) to both sides =

3(5n+1)-5(2n-3)=-2 from here you have a couple of choices I will show you the one I like to use which is foil the 3 =

15n+3-5(2n-3)=-2 now foil the -5 =

15n+3-10n+15=-2 now combine like terms

5n+18=-2 next -18 from both sides

5n=-20 and finally divide the 5

n=-4

Aug 15th, 2014

Studypool's Notebank makes it easy to buy and sell old notes, study guides, reviews, etc.
Click to visit
The Notebank
...
Aug 15th, 2014
...
Aug 15th, 2014
Dec 3rd, 2016
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer