Science
Hi, can someone help

### Question Description

I’m studying and need help with a Physics question to help me learn.

A 7.93 kg box is pulled along a horizontal surface by a force FP of 84.0 N applied at a 47.0º angle. If the coefficient of kinetic friction is 0.35, what is the acceleration of the box?

Student has agreed that all tutoring, explanations, and answers provided by the tutor will be used to help in the learning process and in accordance with Studypool's honor code & terms of service.

Since,Applied force F = 84 N at an angle of 47 degrees .

The horizontal component of the applied force is
F1 = 84 cos (47) = 84 * 0.682 = 57.288 N
Normal Force = N = m g + F sin 47

= 7.93 * 9.8 + 84 sin (47 )

= 77.71 + 61.43 = 139.143 N
f = µ N = 0.35 * 139.143 = 48.7 N
Net force = F1 - f = 57.288 - 48.7 = 8.588 N
F net = m * a --- a

= Fnet / m

= 8.588 / 7.93

= 1.083 m/s2

Furious (72)
Boston College
Review
Review

Anonymous
I was on a very tight deadline but thanks to Studypool I was able to deliver my assignment on time.

Anonymous
The tutor was pretty knowledgeable, efficient and polite. Great service!

Anonymous
Heard about Studypool for a while and finally tried it. Glad I did caus this was really helpful.

Studypool
4.7
Trustpilot
4.5
Sitejabber
4.4

Brown University

1271 Tutors

California Institute of Technology

2131 Tutors

Carnegie Mellon University

982 Tutors

Columbia University

1256 Tutors

Dartmouth University

2113 Tutors

Emory University

2279 Tutors

Harvard University

599 Tutors

Massachusetts Institute of Technology

2319 Tutors

New York University

1645 Tutors

Notre Dam University

1911 Tutors

Oklahoma University

2122 Tutors

Pennsylvania State University

932 Tutors

Princeton University

1211 Tutors

Stanford University

983 Tutors

University of California

1282 Tutors

Oxford University

123 Tutors

Yale University

2325 Tutors