In what direction and at what speed relative to the air must the pilot fly?

Question Description

An airplane must fly at a ground speed of 425 km/h in a direction of 10.0 degrees east of south to be on course and on schedule. If the wind velocity is 25.0 km/h 40.0 degrees east of north. you have to use the resultant to correct the pilot's course

Final Answer

425 km/hr=425,000m/hr 
425,000m/hr=118.1 m/s 

V(x)=sin 10*118.1=20.5 m/s in the x direction 
V(y)=cos 10*118.1=116.3 m/s in the y direction 

this is what the x and y components should be if the plane was flying at the planned speed and heading. 

Now we have to find the components of the wind 

25 km/hr=25,000 m/hr 
25,000 m/hr=6.9 m/s 

6.9m/s at a heading of 40 degrees east of north that is the wind speed 

now we have to break it down into its components 

V(x)=sin 40*6.9=4.4 m/s in the x direction 
V(y)=cos 40*6.9=5.3m/s in the y direction 

now when we add these vectors it should equal the planes planned speed and heading 

V( x total)=20.5 m/s 
20.5 m/s=4.4+x 
16.1 m/s=x 

The plane must fly that fast in the x direction 

V(y total)=116.3 
111 m/s=y 

111 m/s=y 
16.1 m/s=x 

we can use pythagorean theorem to find the hypotenuse 


y=111 m/s 
x=16.1 m/s 
h=112.2 m/s 

the plane must fly about 8.5 degrees east of north

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khakaan (1456)
Purdue University

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