Problem 172 cube length

User Generated

fghqrag1621

Mathematics

Description

What is the percent of increase in the volume of a cube when its edge length is increased by 50%? Express your answer to the nearest tenth.

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Explanation & Answer

V1 = s^3

V2 = (1.5s^3)

V2 = 3.375s^3

Now 

( V2 - V1 )/V1 * 100 = (3.375 s^3 - s^3)/s^3 * 100

( V2 - V1 )/V1 * 100 = (3.375 - 1)s^3/s^3 * 100

                                = (3.375 - 1) *100

                                = 2.375 * 100

                                = 237.5

Hence increased percent volume is 237.5


Anonymous
Excellent resource! Really helped me get the gist of things.

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