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PHY 9C Electricity & Magnetism
Homework 3
Instructions: Upload your answers to Gradescope by 8 May 2020 (Friday) 11:59PM. Make sure that
your work is clearly written and ensure that you have tagged the appropriate pages for the corresponding
problems.
Problem 1: For the resistor networks given below, find the equivalence resistance between points a and b:
(a)
(b)
All the resistors have an identical resistance of R = 1Ω.
(c)
Hint: What is the resistance of the network to the right of c and d?.
Page 1 of 4
Homework 3
PHY 9C
Problem 2:
(a) In the circuit below, C1 = C5 = 8.4 pF and C2 = C3 = C4 = 4.2 pF. A potential difference Vab = 220 V
is applied across the points a and b.
(i) Calculate the equivalent capacitance between the points a and b.
(ii) Calculate the charge on and potential difference across each of the capacitors.
(b) For the capacitor network given below, find the equivalent capacitance between the points a and b
Page 2 of 4
Homework 3
PHY 9C
Problem 3: Consider the circuit shown below.
(a) Find the currents I1 , I2 and I3
(b) Find the potential difference Va − Vb across the two points a and b.
Problem 4: Consider the circuit shown below. The capacitor is initially uncharged. The switch is closed
at t = 0.
(a) Immediately after the switch is closed, what is the current through each resistor?
(b) What is the final charge on and potential difference across the capacitor after a sufficiently long period
of time has elapsed?
(c) After the capacitor has been fully charged, the switch is re-opened. What is the current through each
resistor?
Page 3 of 4
Homework 3
PHY 9C
Problem 5
(a) An initially uncharged capacitor with C = 6.00 µF is connected in series with a resistor R = 5.00 Ω
and a battery E = 50.0V. At a certain instant in time, the resistor is dissipating electrical energy at a
rate P = 250W . What is the amount of energy that has been stored in the capacitor at this point in
time?
(b) Show that, of the total energy drawn from a battery of emf E in charging a capacitor of capacitance C
via a resistor of resistance R, half ends up being dissipated by the resistor.
Page 4 of 4

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