passes through 10,6 perpendicular to the graph of 9x+12y=15

The line perpendicular to 9x+12y=15 is 12x-9y=c where c is a constant.

This passs through 10,6

12*10-9*6=120-54=66=c

The required equatio is 12x-9y =66

or 9y=12x-66

y =12/9 *x-66/9

Secure Information

Content will be erased after question is completed.

Enter the email address associated with your account, and we will email you a link to reset your password.

Forgot your password?

Sign Up