Question Description
Show that the points A(-4,3), B(-2,-2), C(3,0) and D(1,5) frm the verticies of a square.

Final Answer

let=> A(-4,3), B(-2,-2), C(3,0) and D(1,5)
slopes:apply m= (y2-y1) / (x2-x1)
for getting slopes of AB , BC
AB and BC will be perpendicular since the slopes are negative reciprocal.
CD is parallel to AB and perpendicular to BC
AD => (5 - 3)/(1 - 3) = 2/-2 = -1
Length of sides using distance formula: d = √[(x2 - x1)² + (y2 - y1)²]
AB =BC=AD.
