### Question Description

Show that the points A(-4,3), B(-2,-2), C(3,0) and D(1,5) frm the verticies of a square.

## Final Answer

let=> A(-4,3), B(-2,-2), C(3,0) and D(1,5)

slopes:apply m= (y2-y1) / (x2-x1)

for getting slopes of AB , BC

AB and BC will be perpendicular since the slopes are negative reciprocal.

CD is parallel to AB and perpendicular to BC

AD => (5 - 3)/(1 - 3) = 2/-2 = -1

Length of sides using distance formula: d = √[(x2 - x1)² + (y2 - y1)²]

AB =BC=AD.