Mathematics
Parallel and Perpendicular Lines

Question Description

Show that the points A(-4,3), B(-2,-2), C(3,0) and D(1,5) frm the verticies of a square.

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Final Answer

let=> A(-4,3), B(-2,-2), C(3,0) and D(1,5)
slopes:apply m= (y2-y1) / (x2-x1) 
for getting slopes of AB , BC 
AB and BC will be  perpendicular since the slopes are negative reciprocal. 

CD is parallel to AB and perpendicular to BC 
AD => (5 - 3)/(1 - 3) = 2/-2 = -1
Length of sides using distance formula: d = √[(x2 - x1)² + (y2 - y1)²] 
AB =BC=AD. 

Furious (72)
UT Austin

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