Show that the points A(-4,3), B(-2,-2), C(3,0) and D(1,5) frm the verticies of a square.
let=> A(-4,3), B(-2,-2), C(3,0) and D(1,5)slopes:apply m= (y2-y1) / (x2-x1) for getting slopes of AB , BC AB and BC will be perpendicular since the slopes are negative reciprocal. CD is parallel to AB and perpendicular to BC AD => (5 - 3)/(1 - 3) = 2/-2 = -1Length of sides using distance formula: d = √[(x2 - x1)² + (y2 - y1)²] AB =BC=AD.
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