A bag contains eight red tags numbered from 1 to 8 and two blue tags numbered 9 and 10. If Sid selects two tags from the bag at random, with replacement, how many different ordered pairs of tags can he select with at least one red tag?
Total number of ways = 10* 10 =100
No of ways with No red tags =2*2 =4
Number of ways with atleast 1 red tag =100-4 =96
Red blue, Blue red, Red red
This can also be seen as 8*2+2*8+8*8= 16+16+64 =96
Content will be erased after question is completed.
Enter the email address associated with your account, and we will email you a link to reset your password.
Forgot your password?