A bag contains eight red tags numbered from 1 to 8 and two blue tags numbered 9 and 10. If Sid selects two tags from the bag at random, with replacement, how many different ordered pairs of tags can he select with at least one red tag?

Total number of ways = 10* 10 =100

No of ways with No red tags =2*2 =4

Number of ways with atleast 1 red tag =100-4 =96

Red blue, Blue red, Red red

This can also be seen as 8*2+2*8+8*8= 16+16+64 =96

Answer: 96

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