PHY 109 Borough of Manhattan Community College Rotational Equilibrium Lab

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Science

PHY 109

Borough of Manhattan Community College

PHY

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Explanation & Answer

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Part I. Testing the condition of rotational equilibrium
Table 1

M 1w
(g)
100

M c+h (g) = 16.5

X o (m) = 0.499

M 1T (g) = 100 g + M c+h

M 2T (g) = 50g + M c+h

M 1T
(g)
116.5

M 1T
X1
(kg)
(m)
0.1165
0.3
2
d1 = Xo - X1
F 1 = M 1T (kg)  g(m/s )
(N)
(m)
1.1417
0.199
t ccw = t 1 = F 1 (N) d 1 (m)
(N  m)
0.227

M 2w
(g)
50

M 2T
M 2T
(g)
(kg)
66.5
0.0665
2
d2 = X2 - Xo
F 2 = M 2T (kg)  g(m/s )
(N)
(m)
0.6517
0.351
t cw = t 2 = F 2 (N) d 2 (m)
(N  m)
0.229

% difference between t ccw and t cw
0.68
M c+h : Mass of ...


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