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2d+(2^2^2-5)=10 (5-2)+d(12÷6)
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Explanation & Answer
The equation will have the value of d if
2d+(2^2^2-5)=10 (5-2)-d(12÷6)
First we simplify the powers of two then
2^2^2 = 16 , then
2d+(16-5)=10 (5-2) - d(12÷6)
Now we solve the brackets , then
2d + (11) = 10(3) - d(2)
2d + 11 = 30 - 2d
Now adding 2d on both sides, we get
2d + 2d +11 = 30
4d + 11 = 30
Subtracting 11 on both sides, we get
4d = 30 - 11
4d = 19
Now divide 4 on both sides, we get
HENCE d = 19/4
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