2d+(2^2^2-5)=10 (5-2)+d(12÷6)

The equation will have the value of d if

2d+(2^2^2-5)=10 (5-2)-d(12÷6)

First we simplify the powers of two then

2^2^2 = 16 , then

2d+(16-5)=10 (5-2) - d(12÷6)

Now we solve the brackets , then

2d + (11) = 10(3) - d(2)

2d + 11 = 30 - 2d

Now adding 2d on both sides, we get

2d + 2d +11 = 30

4d + 11 = 30

Subtracting 11 on both sides, we get

4d = 30 - 11

4d = 19

Now divide 4 on both sides, we get

HENCE d = 19/4

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