the length of each side of the square is 3 in more than 3 inches more than each side of smaller square. The sum of the area of the square is 149 in power of 2. Find the lenght of the sides of the 2 squares.
Let x be the side of the smaller square
Then (x+3) will be the side of the larger square
x2+(x+3)2 = 149
2x2+6x -140 =0
X= 7 or x=-10
X=-10 is not admissible
Thus the smaller square has side 7
Thus the larger square has side 10
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