the length of each side of the square is 3 in more than 3 inches more than each side of smaller square. The sum of the area of the square is 149 in power of 2. Find the lenght of the sides of the 2 squares.

Let x be the side of the smaller square

Then (x+3) will be the side of the larger square

x^{2}+(x+3)^{2 } = 149

2x^{2}+6x+9 =149

2x^{2}+6x -140 =0

x^{2}+3x-70=0

x^{2}+10x-7x-70=0

x(x+10)-7(x+10)=0

(x+10)(x-7) =0

X= 7 or x=-10

X=-10 is not admissible

Thus the smaller square has side 7

Thus the larger square has side 10

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