Solve the Following Math Equations and Problems Related to Algebra

Anonymous
timer Asked: Sep 6th, 2014
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Question Description

1. 14x-3y/x+10 and x=6,y=5

2. a class has 392 students. 88 more girls than boys. How many boys?

3. Merchant has coffee worth $20 a pounds and mix with 30 pounds of coffee worth $70 a pound get mixture can be sold $50 pound. how many pound of $20 used?

Tutor Answer

Academichelpcenter
School: Duke University

14x-3y/x+10

= 14(6) - 3(5)/6+10

= 84-15/16

= 69/16

2. a class has 392 students. 88 more girls than boys. How many boys?

392-88=304 1/2 of 304 is 142 There 142 boys and 240 girls

Merchant has coffee worth $20 a pounds and mix with 30 pounds of coffee worth $70 a pound get mixture can be sold $50 pound. how many pound of $20 used?

x = number of pounds of coffee worth of $20

(x+30) = number of pounds of mixture of $50

Therefore,

(x)(20) +30(70)= (x+30) (50)

20x +2100 = 50 x + 1500

50x -20 x = 2100 - 1500

30 x = 600

x = 20 pounds

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Tutor went the extra mile to help me with this essay. Citations were a bit shaky but I appreciated how well he handled APA styles and how ok he was to change them even though I didnt specify. Got a B+ which is believable and acceptable.

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