Description
- Prompt the user for a positive integer less than 100.
- Convert the integer into its binary representation, you MUST hard code the solution with your own algorithm with loop NOT using the java buit-in method such as: Integer.toBinaryString(int ).
- Display both the original integer and the binary output.
Explanation & Answer
Here's the Java program that works. For a dollar you don't get much error checking or formatting. Please contact me if you need any additional help. Depending on what you want it could be free or cost a little $$.
import java.util.Scanner;
public class Integer2Binary {
private static Scanner kb = new Scanner(System.in);
public static void main(String[] args) {
System.out.println(
"\nProgram to get postive integer < 100 and convert to binary\n");
int n;
do {
System.out.print("Enter an integer (0<n<100): ");
n = kb.nextInt();
} while (!(0 < n && n < 100));
int nSav = n;
// convert the int to binary:
String binStr = "";
// since n<100, the largest power of 2 that fits will be 64 = 2^6
binStr += n / 64;
n = n % 64;
binStr += n / 32;
n = n % 32;
binStr += n / 16;
n = n % 16;
binStr += n / 8;
n = n % 8;
binStr += n / 4;
n = n % 4;
binStr += n / 2;
n = n % 2;
binStr += n;
// convert string to numbers:
int binNum = Integer.parseInt(binStr);
System.out.println(""
+ "\nThe original decimal integer: " + nSav
+ "\nThis number's binary equivalent is: " + binNum);
}
}
Integer2Binary.java
