 College Physics time and distance question

User Generated

pbyyrtrgvtre

Science

Description

you are standing on the rim of a canyon. You drop a rock and in 7.0s hear the sound of it hitting the bottom (the speed of sound in air is about 340m/s)

Calculate how fast the rock is traveling when it hits the bottom? User generated content is uploaded by users for the purposes of learning and should be used following Studypool's honor code & terms of service. You can hear the sound of rock  after  7 seconds of getting dropped

Here we have to consider the time the rock takes to hit the ground before it makes a sound by hitting

The total time = time taken by rock to hit the ground +time for the sound to return up the canyon

Total time = a+b

a.Time taken for rock to fall/hit the ground

d=1/2gt^2 {g=9.8}

t=square root of (2d/g)

b.Time for the sound to return up the canyon

speed of sound in air is 340m/s

t=d/340(as Distance = Velocity* Time )

Total time =7

So we have

Square root of (2d/9.8) +d/340=7{calculate this and you get the answer)

Solve d

Distance of canyon is

------ sec for the rock to drop

------- sec for the return sound

Let me tell you the other experts answerwhich you bested  is incorrect even the multiplication is wrong just multiply 340*7 =2380  Anonymous
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