### Description

you are standing on the rim of a canyon. You drop a rock and in 7.0s hear the sound of it hitting the bottom (the speed of sound in air is about 340m/s)

Calculate how fast the rock is traveling when it hits the bottom?

## Explanation & Answer

You can hear the sound of rock after 7 seconds of getting dropped

Here we have to consider the time the rock takes to hit the ground before it makes a sound by hitting

The total time = time taken by rock to hit the ground +time for the sound to return up the canyon

Total time = a+b

a.Time taken for rock to fall/hit the ground

d=1/2gt^2 {g=9.8}

** t=square root of (2d/g)**

b.Time for the sound to return up the canyon

speed of sound in air is 340m/s

*t=d/340(as Distance = Velocity* Time )*

Total time =7

So we have

Square root of (2d/9.8) +d/340=7{calculate this and you get the answer)

Solve d

Distance of canyon is

------ sec for the rock to drop

------- sec for the return sound

Let me tell you the other experts answerwhich you bested is incorrect even the multiplication is wrong just multiply 340*7 =2380