In the Mexican jungle, an archaeologist finds a right square pyramid with a base edge length of 60 yards. The pyramid has lateral edge length 50 yards. In square feet, what is the total surface area of the lateral faces of the pyramid?

Surface area of pyramid=4*surface area of each triangle

Each triangle has a base of 60 yards

And height of √(50^{2}-30^{2})=40yards

Area of each triangle=0.5*60*40=1200 yard^{2}

Therefore area of pyramid=4*1200=4800yards^{2}=4800*(3)^{2}=43200 ft^{2}

Secure Information

Content will be erased after question is completed.

Enter the email address associated with your account, and we will email you a link to reset your password.

Forgot your password?

Sign Up