The equation is
y = 1/3tanx
So the general equation to find the period is
y = a tan[b(x-c)] + d
So From general equation , the period is equal to π/b
So from the equation 1 , the value of b is 1,
So b = 1
Then the period of equation 1 is π/1
Which is π
Hence the period is π of the equation 1.
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