The equation is

y = 1/3tanx

So the general equation to find the period is

y = a tan[b(x-c)] + d

So From general equation , the period is equal to π/b

So from the equation 1 , the value of b is 1,

So b = 1

Then the period of equation 1 is π/1

Which is π

Hence the period is π of the equation 1.

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