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need help with linear equation problem

Algebra
Tutor: None Selected Time limit: 1 Day

x+y=24

y=3x+8

Sep 20th, 2014

x+y=24

y=3x+8

from eqn 1, use the value of y=3x+8 to substitute for y, you get

x+(3x+8)=24 solve for thbrackets

x+3x+8=24 take +8 to the right you get

4x=24-8

4x=16 divide both sides by 4

x=4

therefore y will be

y=3x+8

y=3(4) +8 substitute for value of x=24

y=12+8

y=20

therefore

x=4, y=20


Sep 20th, 2014

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