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SOLVE MATH WORD PROBLEM PLEASE WITH STEP BY STEP ANSWERS

Algebra
Tutor: None Selected Time limit: 0 Hours

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Sep 23rd, 2014

4.

cos theta –sin theta =1

When theta = 0 or theta= 3pi/2

cos theta –sin theta =1

Hence 0, 3pi/2 are the roots.

Option b

5.

T (october) = 17 cos (pi/6 *10-7pi/6)+75= cos (3*pi/6)+75= cos (pi/2)+75=75

Option e

6.

(tan u+cot u)(sin u+cos u) =( sinu/cos u+cos u/sinu)(sin u +cosu)

= (sin2u+cos2u)/(sinu cosu)(sin u+cosu)= 1*(sin u+cos u)/(sinu cosu) = 1/cosu +1/sin u

= sec u+ csc u=csc u+sec u

Valid

7.

(sec 2u-1)/sec2 2u = tan22u* cos2u =sin2 2u/ cos2u * cos2u= sin2 2u

Valid


Sep 23rd, 2014

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Sep 23rd, 2014
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