If you begin with 2.56 g of cobalt metal and excess hydrochloric acid, what mass of cobalt(ii) chloride (CoCl2(aq)) can be obtained?
1) Start by writing the balanced reaction:
Co + 2HCl --> CoCl2 + H2
2) Find # of moles of cobalt metal by dividing the mass by its molecular weight:
2.56 g / 58.9 g/mol = 0.0435 moles of Co
3) Find number of moles of CoCl2 by multiplying moles of Cobalt by the molar ratio between CoCl2 and Co using the balanced reaction:
0.0435 mol Co x 1 mol CoCl2 / 1 mol Co = 0.0435 mol CoCl2
4) Find mass of CoCl2 by multiplying moles of CoCl2 by its molecular weight:
0.0435 mol CoCl2 x 129.8 g/mol = 5.64 g of CoCl2
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