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I do not understand this part of chemistry. can someone please help?

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If you begin with 2.56 g of cobalt metal and excess hydrochloric acid, what mass of cobalt(ii) chloride (CoCl2(aq)) can be obtained?

Sep 24th, 2014

1) Start by writing the balanced reaction: 

Co + 2HCl --> CoCl2 + H2

2) Find # of moles of cobalt metal by dividing the mass by its molecular weight:

2.56 g / 58.9 g/mol = 0.0435 moles of Co

3) Find number of moles of CoCl2 by multiplying moles of Cobalt by the molar ratio between CoCl2 and Co using the balanced reaction:

0.0435 mol Co x 1 mol CoCl2 / 1 mol Co = 0.0435 mol CoCl2

4) Find mass of CoCl2 by multiplying moles of CoCl2 by its molecular weight:

0.0435 mol CoCl2 x 129.8 g/mol = 5.64 g of CoCl2



Sep 24th, 2014

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Sep 24th, 2014
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Sep 24th, 2014
Sep 26th, 2017
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