Suppose -pi/2 < theta < 0 and tan theta= -9 Evaluate cos theta and sin theta

tan theta = - 9/1 = perpendicular/base

hypotenus = square root [(-9)^2+1^2] = sq.rt.(81+1) = sq,rt,82

-pi/2 < theta < 0 , theta is in fourth quadrent

cos theta is positive & sin theta is nagetive

cos theta = 1/sq.rt.82

sin theta = -9/sq.rt.82

Secure Information

Content will be erased after question is completed.

Enter the email address associated with your account, and we will email you a link to reset your password.

Forgot your password?

Sign Up