Suppose -pi/2 < theta < 0 and tan theta= -9 Evaluate cos theta and sin theta
tan theta = - 9/1 = perpendicular/base
hypotenus = square root [(-9)^2+1^2] = sq.rt.(81+1) = sq,rt,82
-pi/2 < theta < 0 , theta is in fourth quadrent
cos theta is positive & sin theta is nagetive
cos theta = 1/sq.rt.82
sin theta = -9/sq.rt.82
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