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I'm having problems factoring

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27x^3 8

Sep 24th, 2014

27x3-8= (3x)3-23 = (3x-2)[(3x)2+3x*2+22]= (3x-2)(9x2+6x+4)

or

27x3+8= (3x)3+23 = (3x+2)[(3x)2-3x*2+22]= (3x+2)(9x2-6x+4)


Sep 24th, 2014

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