what is x^2+y4=0 symmetric to?
Calculus

Tutor: None Selected  Time limit: 1 Day 
x axis , y axis , origin? all or none ?
first solve for y
x^2+y4=0 +4 to both sides x^2+y4+4=0+4
x^2+y=4 x^2 to both sides this will isolate y to graph x^2x^2+y=4x^2
y=4x^2 or y=x^2+4 now you can look at the graphing portion
you know that it will intercept the y axis at (0,4) because you have a +4 at the end
the slope is 1/1 because of the 1 in front of the x
now you can do a t chart to see what it will look like... pick three numbers I like to choose a #, 0 , +#
so for ex. 2,0,2
2 in our equation = (2)^2+4 use order of operations
(2)^2 = (2)(2)= 4
(4)+4 = 0 order pair= (2,0)
we already know 0 order pair = (0,4)
now the last is 2 so
(2)^2+4 2^2= 2*2=4
4+4=0
order pair = (2,0)
so from these when you graph you can see that it will be an upside down u and that the center will be the y axis so your line of symmetry or the point where you have equal halfs is the y axis
if you want I will have a worksheet put up in the next 24 hrs with help with this topic and practice problems. If you need it sooner send me a message and let me know
Secure Information
Content will be erased after question is completed.